(2x+1)(x-1)+x^2=3(x-1)(x-2)-3

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Solution for (2x+1)(x-1)+x^2=3(x-1)(x-2)-3 equation: 



(2x+1)(x-1)+x^2=3(x-1)(x-2)-3

We move all terms to the left:

(2x+1)(x-1)+x^2-(3(x-1)(x-2)-3)=0

We multiply parentheses ..

x^2+(+2x^2-2x+x-1)-(3(x-1)(x-2)-3)=0



We calculate terms in parentheses: -(3(x-1)(x-2)-3), so:

3(x-1)(x-2)-3

We multiply parentheses ..

3(+x^2-2x-1x+2)-3

We multiply parentheses

3x^2-6x-3x+6-3

We add all the numbers together, and all the variables

3x^2-9x+3

Back to the equation:

-(3x^2-9x+3)



We get rid of parentheses

x^2+2x^2-3x^2-2x+x+9x-1-3=0

We add all the numbers together, and all the variables

8x-4=0

We move all terms containing x to the left, all other terms to the right

8x=4

x=4/8

x=1/2

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